Chemistry College

## Answers

**Answer 1**

**Answer:**

0.501 M

**Explanation:**

KHP + NaOH → NaKP + H₂O

First we convert 1.513 g of KHP into moles, using its *molar mass*:

1.513 g ÷ 204.22 g/mol = 7.41x10⁻³ mol = 7.41 mmol

As *1 mol of KHP reacts with 1 mol of NaOH*,** in 14.8 mL of the NaOH solution there were 7.41 mmoles of NaOH.**

With the above information in mind we can calculate the molarity of the NaOH solution:

7.41 mmol / 14.8 mL = 0.501 M

## Related Questions

La rapidez a la que cantan los grillos de árbol es de 2.0 ×102 veces por minuto a 27°C

### Answers

**Answer: Accroding to my calculations One time when I went to deny i got lost and I was very tired and hungry So i licked my ice cream then I found my parents and had fun I hope you enjoyed my answer**

**Explanation: Whdd**

Solid strontium chromate, SrCrO4, dissolves into its respective ions at 25°C. Suppose that in a particular solution, [Sr^2+]=6.0x10^-3M. Find the value of Ksp.

A) 3.6 x 10^-5

B) 6.0 x 10^-3

C) 3.6 x 10^-2

D) 7.7 x 10^-2

### Answers

**Answer:**

A) 3.6 x 10^-5.

**Explanation:**

Hello there!

In this case, according to the given information, it turns out firstly necessary to write the equilibrium expression for the dissociation of strontium chromate:

[tex]Ksp=[Sr^{2+}][CrO_4^{2-}][/tex]

Thus, since strontium and chromate ions are in a 1:1 mole ratio, we can tell the concentration of both ions as the same; and therefore, the Ksp is:

[tex]Ksp=(6.0x10^{-3}M)(6.0x10^{-3}M)\\\\Ksp=3.6x10^{-5}[/tex]

Or option A) 3.6 x 10^-5.

Regards!

If the pH of a solution increases from 4.0 to 6.0, the hydronium ion concentration.

A) increases by a factor of 100.

B) decreases by a factor of a 100.

C) decreases by a factor of 1.5

D) increases by a factor of 1.5

explanation and I will give u brainliest

:)

### Answers

**Answer:**

the answer is option B is i guess

If the **pH** of a solution increases from 4.0 to 6.0, the hydronium ion concentration will be increased by a factor 100.

**What is pH?**

The potentialof Hydrogen is the complete version of **pH**. The negative logarithm of H+ ion concentration is known as **pH**. As a result, the definition of **pH** is "potential hydrogen strength." The concentration of hydrogen ions in a particularsolution is known as **pH**, and it is used to determine whether a solution is acidic or basic.

It can be expressed as:

**pH** = -log [[tex]H_{3}O[/tex]]

Calculation of concentration of hydronium ion with **pH** formula:

It can be written as, [[tex]H_{3}O[/tex]] = [tex]10^{pH}[/tex]

Case 1: **pH** = 4

when **pH** = 4, put the value of **pH** in above expression.

[[tex]H_{3}O[/tex]] = [tex]10^{4}[/tex] = 10000.

Case 2: **pH **= 6

when **pH** = 6, put the value of **pH** in above expression.

[[tex]H_{3}O[/tex]] = [tex]10^{6}[/tex] = 1000000.

[[tex]H_{3}O[/tex]]1 / [[tex]H_{3}O[/tex]]2 = 10000/1000000

[[tex]H_{3}O[/tex]]1 / [[tex]H_{3}O[/tex]]2 = 1 / 100

Therefore, the concentration of hydronium will be increased by a factor 100.

To know more about **pH**

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What conclusion best supports Lamar work?

### Answers

**Answer:**

The Answer is - (B)

**Explanation:**

I Just took the test on edg

The acid-base reaction between HCl and NaOH produces a solution with a pH of 7 at the equivalence point (NaCl H2O). Why does an acid-base indicator that changes color at pH 5 or 9 work just as well for this reaction as one that changes color at pH 7

### Answers

**Answer:**

Answer is in the explanation.

**Explanation:**

Before the equivalence point, the pH of the solution of HCl that is titrated with NaOH has a pH <<< 7. When you are adding more NaOH nearing, thus, to the equivalence point the change in pH occurs quickly, and, with 1 drop of excess of NaOH after equivalence, the pH of the solution change to a pH >>> 7

That means the volume added at pH 5 or pH 9 is, almost, the same doing the indicator work just as well as an indicator with change color at pH 7

QUESTION 1 A 2.5-g copper penny is given a charge of 4.0x10-9 C. If no more than one electron is removed from an atom, what percent of the atoms are ionized by this charging process

### Answers

Answer:

[tex]\%X=2.34*10^{-14}\%[/tex]

Explanation:

From the question we are told that:

Mass [tex]M=2.5g[/tex]

Charge [tex]q=4*0*10^{-9}[/tex]

Generally the equation for Total number of Atoms in Penny is mathematically given by

[tex]T_a=\frac{Mass}{atomic weight}*1mole[/tex]

[tex]T_a=\frac{2.5}{63.6}*6.02*10^{23}[/tex]

[tex]T_a=2.34*10^{27}atoms[/tex]

Since Number of electrons in a penny is

[tex]e =nT_a[/tex]

[tex]e=29*2.34*10^{27}[/tex]

[tex]e=6.86*10^{23}[/tex]

Therefore

The percentage of the atoms are ionized by this charging process is given as

[tex]\%X=\frac{T_a}{e}[/tex]

[tex]\%X=\frac{2.34*10^{27}}{6.86*10^{23}}[/tex]

[tex]\%X=2.34*10^{-14}\%[/tex]

Write the reaction of maleic acid with Br2

### Answers

The ammonium ion has a 1+ charge and the sulfide ion has a 2− charge.

What do these layers and their fossils suggest about Earth's history?

ОА.

Lifeforms on Earth have been the same over time.

ОВ.

No lifeforms were present when these layers formed.

OC. Only one kind of lifeform lived where these layers formed.

OD

There have been changes in Earth's lifeforms over time.

### Answers

This is the answer: There have been changes in Earth's life forms over time.

What is the chemical equation for F2 + At- -->

### Answers

**Answer:**

F₂ + 2At --> 2AtF

**Explanation:**

Astatine is a halogen but is not diatomic. It's possible oxidation states are 1⁺, 1⁻, or 5⁺. Fluorine only has the possible oxidation states of 1⁺ or 1⁻.

Write the balanced COMPLETE ionic equation for the reaction when aqueous NiCl₂ and aqueous Na₂S are mixed in solution to form solid NiS and aqueous NaCl. If no reaction occurs, simply write only NR.

### Answers

**Answer:**

**Explanation:**

The chemical reaction of the well-balanced equation is as follows:

[tex]\mathbf{2NiCl_{2(aq)}+2Na_2S_{(aq)} \to 4NaCl_{(aq)}+2NiS_{s}}[/tex]

The aforementioned reaction's ionic equation is:

[tex]\mathbf{2Ni^{2+}_{(aq)}+4Cl^-_{(aq)}+ 4Na^+_{(aq)}+2S^{2-}_{(aq)} \to 4Na^+_{(aq)}+4Cl^-_{(aq)}+2NiS_{(s)}}[/tex]

From above; Na⁺ and Cl⁻ appear on both sides;

Hence, the net ionic equation is:

[tex]\mathbf{2Ni^{2+}_{(aq)}+2S^{2-}_{(aq)} \to 2NiS_{(s)}}[/tex]

1. What is a huge ball of super-heated gases?

O planet

star

solar system

galaxy

### Answers

**Answer:**

star

**Explanation:**

52.1 mL of aqueous 0.255 M Pb(NO3)2 is mixed with 38.5 mL of 0.415 M NaCl. The equation for the precipitate reaction is: Pb(NO3)2 (aq) 2 NaCl (aq) --> PbCl2 (s) 2 NaNO3 (aq) The concentration of Pb2 ion in the solution is _____ M after the reaction is complete.

### Answers

**Answer:**

0.0585 M

**Explanation:**

Pb(NO₃)₂ (aq) + 2NaCl (aq) → PbCl₂ (s) + 2NaNO₃ (aq)

First we calculate the inital number of moles of each reagent, using the *given volumes and concentrations*:

0.255 M Pb(NO₃)₂ * 52.1 mL = 13.3 mmol Pb(NO₃)₂ 0.415 M NaCl * 38.5 mL = 16.0 mmol NaCl

Then we calculate how many Pb(NO₃)₂ moles reacted with 16.0 mmoles of NaCl, using the *stoichiometric coefficients of the reaction*:

16.0 mmol NaCl * [tex]\frac{1mmolPb(NO_3)_2}{2mmolNaCl}[/tex] = 8.00 mmol Pb(NO₃)₂

Now we calculate the remaining number of Pb(NO₃)₂ moles after the reaction:

13.3 mmol - 8.00 mmol = 5.30 mmol Pb(NO₃)₂

Finally we *divide the number of moles by the final volume* to calculate the concentration:

5.30 mmol / (52.1 mL + 38.5 mL) = 0.0585 M

Which one of the mixtures would most likely produce a chemical reaction?

F2 + At- OR At2 + F-

### Answers

**Answer:**

F₂ + At⁻

**Explanation:**

Astatine is the only Halogen that does not exist as a diatomic molecule. One Astatine atom would have a charge of 1⁻. Fluorine is the most electronegative element, and therefore very reactive and commonly forms a diatomic molecule.

2 A + 4 B → 2 C How many mol of B must react with excess A to produce 2 mol of C?

### Answers

**Answer:**

4 mol B

**Explanation:**

**Step 1: Write the balanced generic equation**

2 A + 4 B → 2 C

**Step 2: Establish the appropriate molar ratio**

According to the balanced equation, the molar ratio of B to C is 4:2.

**Step 3: Calculate the moles of B needed to produce 2 moles of C**

2 mol C × 4 mol B/2 mol C = 4 mol B

This portion of the stratosphere if known as the _______.

A.

mesosphere

B.

tropopause

C.

thermosphere

D.

ozone layer

### Answers

The answer to this question is B- tropopause

How much mass does 1 mol of Oz gas have?

### Answers

**Answer:**

31.998, i'm pretty sure.

**Explanation:**

Helppppp

What is the mass of 4.09 x 10^22 molecules of oxygen gas?

1.09 grams

7.69 x 1044 grams

2.17 grams

0.0679 gram

### Answers

**Answer:**

[tex]2.17gO_2[/tex]

**Explanation:**

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the mass of 4.09 x 10^22 molecules of oxygen gas by firstly keeping in mind that that 1 mole of it has a mass of 32.0 g and secondly that 1 mole of any substance contains 6.022x10^23 representative units, in this case, molecules of O2, and thus, the appropriate setup to perform this conversion is shown below:

[tex]4.09x10^{22}molecules \ O_2*\frac{1molO_2}{6.022x10^{23}molecules \ O_2}*\frac{32.0gO_2}{1molO_2} \\\\2.17gO_2[/tex]

Regards!

What is the oxidation state of P in Ca3(PO4)2?

A. -5

B. +3

C. +5

D. -3

### Answers

The **oxidation state** of P in [tex]Ca_3(PO_4)_2[/tex] is +5. In the compound [tex]Ca_3(PO_4)_2[/tex], there are 3 Ca ions, each with an oxidation state of +2, and 2 [tex]PO_4[/tex] ions. The correct answer is option C.

To find the oxidation state of P, we need to use the fact that the compound has a **neutral overall charge** and the oxidation states of all the atoms in the compound must add up to zero. Since the oxidation state of Ca is +2, the total positive charge from the Ca ions is +6. Therefore, the total negative charge from the PO4 ions must be -6. Each [tex]PO_4[/tex] ion has a charge of -3, so the total charge from the two [tex]PO_4[/tex] ions is -6. In [tex]PO_4[/tex], the oxidation state of O is -2. Let the oxidation state of P be x. Since there is 4 O **atoms **per [tex]PO_4[/tex] ion, the total negative charge from the O atoms is -12. Using the fact that the overall charge is zero, we can set up the following equation: 2x + (-12) = -6 Simplifying, we get 2x = +6 - (-12) = +18 Solving for x, we get x = +9/2 = +4.5. However, the oxidation state of P must be a whole number, so we round to the nearest **integer **and get: +5. Therefore, the oxidation state of P in [tex]Ca_3(PO_4)_2[/tex] is +5 and the correct answer is option C.

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Given the following set of atoms, write a bond-line formula for a possible constitutional isomer for the compound. Show all formal charges and lone pairs.C atoms H atoms Other3 6 2 Br atoms

### Answers

**Answer:**

**Explanation:**

Isomers are compounds with the same molecular formula but chemically distinctive structures. Compounds that vary in connectivity, or how the component atoms are related to one another, are known as constitutional isomers. They have distinct functional groups and bonding patterns according to the sequence in which the atoms are linked together.

From the information given:

The compound given is C₃H₆Br₂ and the constitutional isomer of the compound can be seen in the image attached below.

The formal charges are calculated as follows:

Formal charge = valence electron - 1/2(bonding electron) - lone electron

For Br:

Formal charge = 7 - 1/2(2) - 6

Formal charge = 7 - 1 - 6 = 0

For C:

Formal charge = 4 - 1/2(8) - 0

Formal charge = 4 - 4 = 0

For H:

Formal charge = 1 - 1/2(2)

Formal charge = 1 - 1 = 0

3 enzimas presentes en nuestro organismo e indique en que procesos actúan

### Answers

**Answer:**

ATP asa, Helicasa, Proteasa, ARN polimerasa

**Explanation:**

Las enzimas son un tipo de biomoleculas que se corresponden con las proteinas.

Al momento de referirse a ellas, se utiliza la terminación asa.

ATPasa → Sintetizando ATP para el funcionamiento celular

Helicasa → Abre las hebras de ADN permitiendo el paso de la horquilla para el proceso de replicación de ADN.

Proteasas → Enzimas que degradan proteinas mal plegadas, rompen los enlaces peptídicos.

ARN polimerasa → Sintesis de ARN mensajero a partir de ADN en el proceso de la Transcripción. Se la puede conocer a veces, como primasa.

How many grams of gas must be released from a 32.0 L sample of CO2(g) at STP to reduce the volume to 16.6 L at STP?

### Answers

**Answer:**

30.3 g

**Explanation:**

At STP, **1 mol of any gas will occupy 22.4 L**.

With the information above in mind, we calculate how many moles are there in 32.0 L:

32.0 L ÷ 22.4 L/mol = 1.43 mol

Then we calculate how many moles would there be in 16.6 L:

16.6 L ÷ 22.4 L/mol = 0.741 mol

The difference in moles is:

1.43 mol - 0.741 mol = 0.689 mol

Finally we convert 0.689 moles of CO₂ into grams, using its *molar mass*:

0.689 mol * 44 g/mol = 30.3 g

What phenomenon is exhibited by an element P37 17 and P35 17

### Answers

**Answer:**

Isotopy

**Explanation:**

Isotopes are various forms of atoms of the same element with varying numbers of neutrons. Although all isotopes of an element possessthe same atomic number as well as the number of protons, buttheir atomic weights differ. Chemically, isotopes of the same element have identical characteristics, but nuclear properties differ.

From the given information;

[tex]\mathbf{P_{17}^{37} }[/tex] and [tex]\mathbf{P_{17}^{35} }[/tex] are called **isotopes** and the phenomena exhibited between is known as **(isotopy)**

Which of the following can be mixed in solution with H2CO3 to make a buffer?

### Answers

**Answer:**

Sodium hydroxide solution.

**Explanation:**

because it is a strong base. Since carbonic acid is a weak acid, a solution formed resists change in pH on addition hence buffer formed.

Sodium hydroxide **solution **can be can be mixed in solution with H2CO3 to make a **buffer**.

**What is buffer?**

A **buffer** would be a **solution** that could withstand pH changes when acidic as well asbasic components are added.

**What is solution ?**

The term "**solution**" was mostfrequently associated with the liquid form of matter, however gases as well as solids can also form **solutions**.

A traditional **buffer** is made up of a weak acid includingits conjugate salts, such as carbonic acid (H2CO3) as well as sodium bicarbonate (NaHCO3) or sodium bicarbonate with calcium carbonate.

Sodium hydroxide **solution **can be can be mixed in **solution** with H2CO3 to make a **buffer**.

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A gas mixture being used to simulate the atmosphere of another planet consists of 320 mg of methane, 175 mg of argon, and 225 mg of nitrogen. Th e partial pressure of nitrogen at 300 K is 15.2 kPa. Calculate (a) the volume and (b) the total pressure of the mixture.

### Answers

Answer:

The total pressure is 61.4 kPa, and the volume is 1.31 L.

Explanation:

Based on the given information, a gas mixture comprising 320 mg or 0.320 grams of CH4, 175 mg or 0.175 grams of Ar, and 225 or 0.225 grams of N. The number of moles of the gases presents within the mixture can be determined by using the formula,

Number of moles = Mass/ molecular mass

The molecular mass of methane is 16.04 grams per mole, the molecular mass of Argon is 40 grams per mole, and the molecular mass of Nitrogen is 28.02 grams per mole.

Now, the number of moles of CH4 is,

= 0.320 grams/ 16.04 grams per mole

= 0.0199 moles

The number of moles of Ar is,

= 0.175 grams/40 grams per mole

= 0.0044 moles

The number of moles of N2 is,

= 0.225 grams/28.02 grams per mole

= 0.0080 moles

The partial pressure of nitrogen given is 15.2 kPa or 0.15 atm. Thus, the partial pressure of other two gases will be,

CH4 = (15.2 kPa) (0.0199 moles)/(0.0080 moles)

= 37.8 kPa

Ar = (15.2 kPa) (0.0044 moles)/(0.0080 moles)

= 8.36 kPa

Therefore, the total pressure is 15.2 + 37.8 + 8.36 = 61.4 kPa or 0.606 atm

The total volume can be determined by using the formula,

V = nRT/P

Here n is the total number of moles of the gas, which is 0.0323 moles.

Now putting the values we get,

V = (0.0323 moles) (0.0826 atm*L/mol*K)(300 K)/(0.606 atm)

V = 1.31 L

Which bodies of water in the list are found to the west of the Philippines?

### Answers

**Answer:**

South China sea

**Explanation:**

To the west is the South China Sea, to the east the Philippine Sea and the Pacific Ocean, and to the south the Celebes Sea (or Sulawesi Sea).

Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures PA and inside the flasks are measured.

a. PA will be greater than

b. PA will be less than PB

c. PA will be equal to PB

d. It's impossible to predict whether PA or will be greater without more information.

### Answers

**The question is incomplete, the complete question is:**

Liquid A is known to have a lower viscosity and lower vapor pressure than Liquid B. Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures [tex]p_A[/tex] and [tex]p_B[/tex] inside the flasks are measured.

a. [tex]p_A[/tex] will be greater than

b. [tex]p_A[/tex] will be less than [tex]p_B[/tex]

c. [tex]p_A[/tex] will be equal to [tex]p_B[/tex]

d. It's impossible to predict whether [tex]p_A[/tex]** **or will be greater without more information.

**Answer:**** The correct option is b) **[tex]p_A[/tex]** will be less than **[tex]p_B[/tex]

**Explanation:**

**Vapor pressure** is defined as the equilibrium pressure which is exerted by the vapor phase to be in thermodynamic equilibrium with its condensed state (liquid phase) in a closed system at a given temperature.

**We are given:**

Vapor pressure of A < Vapor pressure of B

This means that a lesser number of gaseous molecules will form over its surface and thus, will experience lower pressure.

Thus, [tex]p_A<p_B[/tex]

**Hence, the correct option is b) **[tex]p_A[/tex]** will be less than **[tex]p_B[/tex]

how do i convert 145.6grams of Iron sulphide into iron and sulfur

### Answers

So basically first try to find the co2 then convert it

Draw and upload the structures

of the following derivatives of

the carboxylic acids

a. Ethyl 2-hydroxypropanoate

b. Butyl 3,3-dimethyhexanoate

c. N-Ethyl-N-methylbenzamide

d. 2,3-Dibromohexanamide

### Answers

**Answer:**

Draw and upload the structures

of the following derivatives of

the carboxylic acids:

a. Ethyl 2-hydroxypropanoate

b. Butyl 3,3-dimethyhexanoate

c. N-Ethyl-N-methylbenzamide

d. 2,3-Dibromohexanamide

**Explanation:**

a. Ethyl 2-hydroxypropanoate

indicates that the given molecule has -oate suffix that means it has an ester(R-COO-R') functional group.

Prop- indicates that the main carbon chain has three carbon atoms.

Ethyl group at the second position is the substituent.

b. In this molecule has also -oate functional group which means it has an ester functional group.

The rootword hex-indicates that the main carbon chain has six carbons.

Butyl-3,3-dimethyl group is the substituent.

c. N-ethyl-N-methylbenzamide

In this molecule, the aimde group indicates the presence of -CONH2 group.

N-methyl group prefix indicates that the methyl group is attached to N-atom.

N-ethyl prefix indicates the presence of ethyl group to N-atom.

d. 2,3-dibromohexanamide indicates the presence of amide functional group and two bromo groups as substituents at the second and third carbons.

The structures of all the compounds are shown below:

**Answer:**** The structures of all the acid derivatives are attached below.**

**Explanation:**

**Some of the acid derivatives are:**

EstersAmidesAcid anhydridesAcid halides

To name a compound, first look for the longest possible carbon chain.

**Amide group **is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.

Esters are a kind of organic molecules having functional groups, where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.

These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.

**For (a):**** Ethyl 2-hydroxypropanoate**

The longest possible carbon chain has 3 carbon atoms and prefix used will be 'prop-'.

A hydroxy (-OH) group is attached to the 2nd position.

The structure is attached in the image below.

**For (b):**** Butyl 3,3-dimethyhexanoate**

The longest possible carbon chain has 6 carbon atoms and prefix used will be 'hex-'.

2 methyl groups are attached at the 3rd position

The structure is attached in the image below.

**For (c):**** N-Ethyl-N-methylbenzamide**

The longest possible carbon chain is a benzene ring

1 methyl and 1 ethyl groups are attached directly to the N-atom

The structure is attached in the image below.

**For (d):**** 2,3-Dibromohexanamide**

The longest possible carbon chain has 6 carbon atoms and prefix used will be 'hex-'.

2 bromo groups are attached at the 2nd and 3rd position

The structure is attached in the image below.

PLEASE HELP

Let’s say a colleague working in the lab needs to create a solution containing 97.9 grams of NaCl. If she has a 3.0 M stock solution of NaCl dissolved in water, how many liters of the stock solution would she need to have 97.9 grams NaCl? Remember the molar mass of NaCl is 58.44 g/mol.

### Answers

**Answer: There are 0.558 liters of the stock solution would she need to have 97.9 grams NaCl.**

**Explanation:**

**Given:** Molarity = 3.0 M

Mass of NaCl = 97.9 g

Molar mass of NaCl = 58.44 g/mol

As number of moles is the mass of substance divided by its molar mass.

So, moles of NaCl are calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{97.9 g}{58.44 g/mol}\\= 1.675 mol[/tex]

**Molarity is the number of moles of a substance present in liter of a solution.**

Therefore, volume of given solution is calculated as follows.

[tex]Molarity = \frac{moles}{Volume (in L)}\\3.0 M = \frac{1.675 mol}{Volume}\\Volume = 0.558 L[/tex]

Thus, we can conclude that **there are 0.558 liters of the stock solution would she need to have 97.9 grams NaCl.**

What is 0.29km in mm

### Answers

I believe it’s 290000 millimeters

Answer: 290,000 mm

Explanation:

1 km=1,000,000 mm

0.29 km= 290,000 mm